1.

A disc is rotatin g aro u n d its cen tre in a horizontal plane at the rate of 60 rotation/ minute. A coin (1A^(st)) is placed at a distance of 18 cm and 2^(nd) similar coin 20 cm from its centre.The co-efficient of static friction between the disc and the coins is 0.2. Which coin will be thrown away from the disc ? Which coin will keep rotating with the disc ?

Answer»

both COINS THROWN away
2ndcoin KEEP rotating1st coin thrown away
both coins keep rotating
1st coin keep rotating 2nd coin thrownaway

Solution :Supposemass of each coin m
for the circularmotioncentrifugalforce`le ` maximumstaticfriction.
`(mv^(2))/(r ) le f _(s)`
Timerequiredfor 60rotationis 60second Timerequiredfor 1rotationis
`T = (60)/(60)=1`
Now linearvelocity`v=(2pi r)/( T )` and`f_(s(max))= mu_(s ) N = mu_(s ) MG`
fromequation(1)
`(m )/(T) xx (2pi r)/(T ) le mu_(s ) mg`
`le((0.2).(10).(1)^(2))/(4xx 10)`
`le0.05 m`
`r le m`
boththe coin from the 18 cm and 20 cmdistancefrom the centreare thrownaway .


Discussion

No Comment Found