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A disc of mass 2 kg and diameter 40 cm is free to rotate about an axis passing through its centre and perpendicular to its plane. If a force of 50 N is applied to the disc tangentially Its angular acceleration will beA. `100 rad//s^(2)`B. `25 rad//s^(2)`C. `250 rad//s^(2)`D. `500 rad//s^(2)` |
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Answer» Correct Answer - C `tau = I alpha` `therefore alpha =(tau)/(I)=(rF)/(I)=(0.2xx50)/(mR^(2)/2)=(10xx2)/(2xx0.2xx0.2)` `= 250 rad//s^(2)` |
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