A disc of moment of inertia `9.8//pi^(2)kg m^(2)` is rotating at 600 rpm . If the frequency of rotation changes from 600 rpm to 300 rpm, then what is the work done?A. 1470 JB. 1452 JC. 1567JD. 1632J

A disc of moment of inertia `9.8//pi^(2)kg m^(2)` is rotating at 600 r

1.	A disc of moment of inertia `9.8//pi^(2)kg m^(2)` is rotating at 600 rpm . If the frequency of rotation changes from 600 rpm to 300 rpm, then what is the work done?A. 1470 JB. 1452 JC. 1567JD. 1632J
Answer» Correct Answer - A Work done `= Delta K.E. = (1)/(2)I(omega_(2)^(2)-omega_(1)^(2))` `= (9.8)/(2xx pi^(2))xx 4pi^(2)` `(n_(1)^(2)-n_(2)^(2))=19.6xx75` = 1470 J.

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A disc of moment of inertia `9.8//pi^(2)kg m^(2)` is rotating at 600 rpm . If the frequency of rotation changes from 600 rpm to 300 rpm, then what is the work done?A. 1470 JB. 1452 JC. 1567JD. 1632J

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