1.

A discrete random variable X has the following probability distribution the value of C and the mean of the distribution are A. `1/(10) and 3.66`B. `1/(20) and 2.66`C. `1/(15) and 1.33`D. None of these

Answer» Correct Answer - A
Since `Segmap=1` we have
`C+2C+2C+3C+C^2+2C^2+7C^2+C=1`
`rArr" "10C^2+9C-1=0`
`rArr" "(10C-1)(C+1)=0`
`rArr" "C=1/(10),C=-1`
Therefore, the permissible value of `C=1/(10)`
Mean `sum_(i=1)^nx_ip_1=sum_(i=1)^7x_ip_i`
`=1xx1/(10)+2xx2/(10)+3xx2/(10)+4xx3/(10)+5(1/(10))^2+6xx2(1/(10))^2+7(7(1/(10))^2+1/(10))`
`=1/(10)+4/(10)+6/(10)+(12)/(10)+5/(100)+(12)/(100)+(49)/(100)+7/(10)`
=3.66


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