A distance of 355 m can be covered byRohan in 1 minute 15 seconds. If

1.	A distance of 355 m can be covered byRohan in 1 minute 15 seconds. If he has tocover 1065m, then how much time will hetake?a) 3 min 45 sec ) 2 min 65 secc) 4 min 35 sec d) 3 min 55 sec,
Answer» Divide different levels of the same language The time taken by Rohan to cover 355 m = 1 min15 sec But 1065 = 3 × 355 Therefore The time taken by Rohan to cover 1065 kms = 3 × ( The time taken to cover 355kms ) = 3 × 1 min 15 sec = 3 min 45 seconds. 1 min 15 sec = 75 minSpeed = distance/time = 355/75 = 71/15Time = distance/speed = 1065/(71/15) = (1065 × 15)/71 = 15 × 15 = 225 sec = 3 min 45 sec Distance of 355 m can be covered in 1 minute 15 seconds or 75 seconds Then,Distance of 1 m can be covered in 75/355 seconds Therefore,Distance of 1065 m can be covered in106575/355 = 375 = 225 secods= 3 min 45 seconds (a) is correct option 3 min 45 sec will be the ans 3min 45 sec need to cover 1065m

A distance of 355 m can be covered byRohan in 1 minute 15 seconds. If he has tocover 1065m, then how much time will hetake?a) 3 min 45 sec ) 2 min 65 secc) 4 min 35 sec d) 3 min 55 sec,

Answer»

Divide different levels of the same language

The time taken by Rohan to cover 355 m = 1 min15 sec

But 1065 = 3 × 355

Therefore

The time taken by Rohan to cover

1065 kms

= 3 × ( The time taken to cover 355kms )

= 3 × 1 min 15 sec

= 3 min 45 seconds.

1 min 15 sec = 75 minSpeed = distance/time = 355/75 = 71/15Time = distance/speed = 1065/(71/15) = (1065 × 15)/71 = 15 × 15 = 225 sec = 3 min 45 sec

Distance of 355 m can be covered in 1 minute 15 seconds or 75 seconds

Then,Distance of 1 m can be covered in 75/355 seconds

Therefore,Distance of 1065 m can be covered in1065*75/355 = 3*75 = 225 secods= 3 min 45 seconds

(a) is correct option

3 min 45 sec will be the ans

3min 45 sec need to cover 1065m