1.

A does half as much work as B, and C does half as much work as A and B together. If C alone can finish the work in 40 days, then all together will finish the work in (B) 15 days (A) `13(1/3)` days (D) 30 days (C) 20 days

Answer» Let work done by B in tme(t)=x
Let work done by A in time(t)=x/2
Let the work done C=`1/2(x+x/2)=3/4x`
1 day work of C=1/40
t days work=`t/40=3/4x`
`x=t/30`
`t/60+t/30+t/40`
`(2t+4t+3t)/120`
`3/40t`
t=40/3 days.


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