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A does half as much work as B, and C does half as much work as A and B together. If C alone can finish the work in 40 days, then all together will finish the work in (B) 15 days (A) `13(1/3)` days (D) 30 days (C) 20 days |
Answer» Let work done by B in tme(t)=x Let work done by A in time(t)=x/2 Let the work done C=`1/2(x+x/2)=3/4x` 1 day work of C=1/40 t days work=`t/40=3/4x` `x=t/30` `t/60+t/30+t/40` `(2t+4t+3t)/120` `3/40t` t=40/3 days. |
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