A door of moment of inertia 4 kg m^(2) is at rest. When a torque of 2 pi Nm acts on it find its angular acceleration. Find also its angular velocity after 1 s.

A door of moment of inertia 4 kg m^(2) is at rest. When a torque of 2

1.	A door of moment of inertia 4 kg m^(2) is at rest. When a torque of 2 pi Nm acts on it find its angular acceleration. Find also its angular velocity after 1 s.
Answer» <html><body><p></p>Solution :`alpha=(<a href="https://interviewquestions.tuteehub.com/tag/tau-663951" style="font-weight:bold;" target="_blank" title="Click to know more about TAU">TAU</a>)/(I)=(2pi)/(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)=(<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)rad//s^(2)` <br/> `omega_(2)-omega_(1)=alphat""omega_(2)=(pi)/(2)<a href="https://interviewquestions.tuteehub.com/tag/xx1-1463705" style="font-weight:bold;" target="_blank" title="Click to know more about XX1">XX1</a>` <br/> `omega_(2)=1.57` rad/sec.</body></html>