A door of moment of inertia 4kgm^(2) is at rest. When a torque of 2piNm^("acts") on it find its angular acceleration. Find also its angular velocity after 1s .

A door of moment of inertia 4kgm^(2) is at rest. When a torque of 2piN

1.	A door of moment of inertia 4kgm^(2) is at rest. When a torque of 2piNm^("acts") on it find its angular acceleration. Find also its angular velocity after 1s .
Answer» SOLUTION :`ALPHA=(tau)/(I)=(2pi)/(4)=(pi)/(2)rad//s^(2)` `omega_(2)-omega_(1)=ALPHAT` `omega_(2)=(pi)/(2)xx1` `omega_(2)=1.57rad//sec`