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A double convex lens made of glass (mu=1.5) is immersed in water (mu=4//3). If its focal length in air is 'F', then the focal length in water will be : |
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Answer» Solution :`(1.5-1)((1)/(R_(1))-(1)/(R_(2)))=(1)/(F)` `((1.5)/(4)xx3-1)((1)/(R_(1))-(1)/(R_2))=(1)/(F)` `(0.5)/(0.5)xx4=(F')/(F)rArrF'=4F""]` |
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