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A double convex lens of focal length 15 cm is used as a magnifying glass in order to produce an erect image which is 3 times magnified. What is the distance between the object and the lens ? |
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Answer» f = 15 cm m = 3 Magnifying power `(m)=(-upsilon)/(u)=(f)/(f-u)` `3=(15)/(15-u)` `45-3u=15` `3u=45-15` `3u=30` `u=(30)/(3)=10cm.` |
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