(a) Draw the circuit diagrma of an 1-p-transistor with emitter-base junction forward biased and collector-base junction reverse biased. Describe briefly how the motion of charge carriers in the transistor constitutes the emitter current (I_E), the base current (I_B) and the collector current (I_C). Hence deduce the relation l_E= I_B + I_C

(a) Draw the circuit diagrma of an 1-p-transistor with emitter-base ju

1.	(a) Draw the circuit diagrma of an 1-p-transistor with emitter-base junction forward biased and collector-base junction reverse biased. Describe briefly how the motion of charge carriers in the transistor constitutes the emitter current (I_E), the base current (I_B) and the collector current (I_C). Hence deduce the relation l_E= I_B + I_C
Answer» Solution :Thecircuitdiagramis showshere: The emitter-BASE junction, being forward biased, the majority charge CARRIERS (electrons), from the emitter, flow into the base region CONSTITUTING the emitter current (`l_E`). The base region, being very thin, only a (very) SMALL fraction, of these small base current (`I_B`) The majority of these charge carriers, are ATTRACTED by the (reverse biased) collector. These make up the collector current (`I_C`). `I_E=I_C +I_B`

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