1.

A driver of train A, moving at a speed 30 ms^(-1), sights another train B going on the same track and in the same direction with speed 10 ms^(-1). He immediately applies brake that gives his train a constant retardation of 2 ms^(-2). What must be the minimum distance between trains in order to avoid a collision ?

Answer»

Solution :The initial velocity of the train,
`v_(0) = v_(AB) = v _(A) -v _(B) = 30 - 10 = 20 ms ^(-1)`
Now `v ^(2) -v _(0) ^(2) = 2ax,`
here, `v =0, v _(0) = 20 , a =- 2MS ^(-2)`
`therefore (0) ^(2) - (20) ^(2) = 2 (-2) x`
`therefore (-400)/(-4) =x`
`therefore x = 100 m`
ACCIDENT can be avoided if the minimum DISTANCE 100 m is kept between two trains.


Discussion

No Comment Found