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A drop of a solution (volume 0.05 mL) contains 3.0xx10^(-6) mole of H^(+) ions. If the rate constant of disappearance of H^(+) ions is 1.0xx10^(-7)" mol L"^(-1)s^(-1), how long would it take for H^(+) ions in the drop to disappear ? |
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Answer» Solution :As the units of RATE constant are `"mol L"^(-1)s^(-1)`, this means disappearance of `H^(+)` ions is a reaction of zero order. For `100%` reaction to COMPLETE (i.e., complete disappearance of `H^(+)` ions) `t_(100%)=([A]_(0))/(K)=([H^(+)])/(k)` 0.05 mL of the DROP contains `H^(+)` ions `=3.0xx10^(-6)` mole `:.100" mL of the solution will contain "[H^(+)]=(3.0xx10^(-6))/(0.05)xx1000=6xx10^(-2)` i.e., `[H^(+)]=6xx10^(-2)" M"` `:.t_(100%)=(6xx10^(-2))/(1xx10^(7))=6xx10^(-9)s` |
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