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A drop of liquid of density `rho` is floating half-immersed in a liquid of density `d`. If `rho` is the surface tension the diameter of the drop of the liquid isA. `sqrt((sigma)/(g(2rho-d)))`B. `sqrt((2sigma)/(g(2rho-d)))`C. `sqrt((6sigma)/(g(2rho-d)))`D. `sqrt((12sigma)/(g(2rho-d)))` |
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Answer» Correct Answer - D `2pirsigma+1/2xx4/3pir^(3)dg=4/3rhog` or `2pirsigma=(pir^(3)g)/3[4rho-2d]` or `r^(2)=(3xx2pisigma)/(pig(2rho-2d)` or `r^(2)=(3sigma)/(g(2rho-d)` or `r=sqrt((3sigma)/(g(2rho-d)))` Diameter `=2r=sqrt((12sigma)/(g(2rho-d))` |
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