1.

A drop of olive oil of radius 0.20mm spreads as a film on the water surface. Calculate the molecular size of the olive oil ifthe film is (a) circular, with a radius size of 10 cm (b) retangular, with size 20cm xx 10 cm.

Answer»

Solution :Radius of oil drop `=0.20mm`
(a) THICKNESS of olive oil film `=("Volume of oil drop")/("Area of the film")`
`=((4)/(3)pi xx(0.020)^(3) cm^(3))/(pi xx (10)^(2) cm^(2))`
`=(4)/(3)xx(20)^(3)xx10^(-11) cm`
`=1.067xx10^(-7)cm`
ASSUMING that the film has one molecular thickness, molecular size of olive oil `=1.067xx10^(-7)cm`.
(b) Thickness of olive oil film `=("Volume of oil drop")/("Area of the film")`
`=((4)/(3)pixx(0.020)^(3)cm^(3))/((20xx10)cm^(2))`
`=(4)/(3)pi xx ((20)^(3))/(2)xx10^(-11)cm`
`=1.674xx10^(-7)cm`
Molecular size of olive oil `=1.674xx10^(-7)cm`.


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