A drop of water detaches itself from the exit of a tap when [sigma= surface tension of water, rho= density of water, R = radius of the tap exit, r = radius of the drop]

A drop of water detaches itself from the exit of a tap when [sigma= su

1.	A drop of water detaches itself from the exit of a tap when [sigma= surface tension of water, rho= density of water, R = radius of the tap exit, r = radius of the drop]
Answer» ` R gt (2/3(Rsigma)/(rho g))^((1)/(3))` ` r gt (2/3(Rsigma)/(rho g))` `(2sigma)/(r ) gt "atmospheric pressure"` `r gt ((2)/(3)(R sigma )/(rho g)^(2/3))` Solution :UPWARD force due to surface tension `=Fsintheta=sigmaxx2piR sin theta` `=sigmaxx2piRxxR/r=(2pisigmaR^2)/(r )` Weight of the drop of water = MG `=4/3 pi r^3 rho g` The drop will detach if, `4/3pi r^3 rho g gt (2pi sigma R^2)/(r ) or, r^4 gt (3 sigma R^2)/( 2 rho g)` `thereforer gt ((3)/(2) (sigma R^2)/(rho g))^(1/4)` NONE of the options are CORRECT.