A drop of water of volume 0.05cm^(3) is pressed between two glass plates, as a consequence of which it spreads and occupies an area of 40cm^(2). If the surface tension of water is 70 dyne/cm, then the normal force required to separate out the two glass plates will be in Newton

A drop of water of volume 0.05cm^(3) is pressed between two glass plat

1.	A drop of water of volume 0.05cm^(3) is pressed between two glass plates, as a consequence of which it spreads and occupies an area of 40cm^(2). If the surface tension of water is 70 dyne/cm, then the normal force required to separate out the two glass plates will be in Newton
Answer» 90 45 22.5 450 Answer :B