A drop of water of volume 0.05cm^3 is pressed between two glass plates, as a consequence of which it spreads and occupies an area of 40cm^2. If the surface tension of water is 70 dyne/cm, then the normal force required to separate out the two glass plates will be in newton)

A drop of water of volume 0.05cm^3 is pressed between two glass plates

1.	A drop of water of volume 0.05cm^3 is pressed between two glass plates, as a consequence of which it spreads and occupies an area of 40cm^2. If the surface tension of water is 70 dyne/cm, then the normal force required to separate out the two glass plates will be in newton)
Answer» 90 45 22.5 450 Answer :B