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A drunkard waking in a borrow lane takes ` 6 ` steps forward and `4` steps backward, following againg ` 6` steps forward and ` 4` steps backward and so on Each step is ` 1 `m long and requires ` 1s`. Determine how long the drunkard takes to fall in a pit ` 15 m` away from the start.

Answer» Efferctive distance travelled by drunkard in ` 10 ` steps ` =- 4 = 2 m`.
Therefore he takes ` 50 ` steps to moves `10 m`. Now he will hve to civer ` 5 m` more to reach the pot. For this he has to take only `5` forward steps. Thus total steps taken to fall in pit ` = 50 + 5 = 55 `
As each step is taken in ` 1 s`. so the time taken to fall in pit ` = 55 s`.


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