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A duster weighs `0.5N`. It is pressed against a vertical board with a horizontal force `11N` If the co-efficient of friction is `0.5` the mimmum force that must be applied on the duster parallel to the board to move it upwards is .A. `0.4N`B. `0.7N`C. `6N`D. `7N` |
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Answer» Correct Answer - C `F_(up) = f + mg, f = mu N,N =F` |
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