1.

A duster weighs 0.5N. It is pressed against vertical board with a horizontal force of 11N. If the co-efficient of friction is 0.5 the minimum force that must be applied on the duster parallel to the board to move it upwards is

Answer»

0.4 N
0.7 N
6N
7N

Solution :`F_(up)=F+mg, f=muN, N=F`


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