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A dynamometer D is attached to two bodies of masses M=6 kg and m=4 kg. Force F=20 N and f=10N are applied to the masses as shown. The dynometer reads |
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Answer» 10N `a=(F-f)/(M+m)=(20-10)/(6+4)=1 ms^(-2)"" ` (TOWARDS left) Let `F_(0)` be the reading of DYNAMOMETER, then equation of motion of MASS m would be, `implies F_(0)=f+ma=10+(4)(1)=14N` |
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