InterviewSolution
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InterviewSolution
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(a) Express the relationship amongst cell constant , resistance of the solution in the cell and conductivity of the solution . How is molar conductivity of a solute related to conductivity of its solution ? (b) Calculate the equilibrium constant for the reaction `Fe_((s)) + Cd_((aq))^(2+) hArr Fe_((aq))^(2+) + Cd (s)` (Given : `E_(Cd^(2+)|Cd)^(@) = 0.40 V , E_(Fe^(2+) |Fe)^(@) = -0.44 V`). |
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Answer» (b) `E_("cell")^(@) = E_("cathod")^(@) - E_("anode")` `= -0.40 - (-0.44)` = `-0.40 + 0.44 = 0.04V` Since `" " E_("cell")^(@) = (0.059)/(n) "log" Kc` `0.04 = (0.059)/(2) "log" Kc` log Kc = `(2xx 0.04)/(0.059) = 1.356` Kc = anti-log `(1.356) = 22.70` |
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