1.

(a) Factorise : `x^(2) - (z-5)x - 5z` (b) Factorise : `x^(2) + x - y + y^(2) - 2xy`

Answer» (a) `x^(2) - (z-5)x - 5z`
= `x^(2) - xz + 5x - 5z = x(x-z) + 5(x-z) = (x-z) (x + 5)`
`therefore x^(2) - (z-5)x - 5z = (x-z) (x + 5)`
(b) `x^(2) + x - y + y^(2) - 2xy`
`= x^(2) + y^(2) - 2xy + x - y = (x-y)^(2) + 1(x-y) = (x-y) (x+y + 1)`
`therefore x^(2) + x - y + y^(2) - 2xy = (x-y) (x+y + 1)`


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