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A factory, producing methanol, is based on the reaction : CO+2H_(2)rarr CH_(3)OH ltBRgt Hydrogen and carbon monoxide are obtained by the reaction CH_(4)+H_(2)Orarr CO+3H_(2) Three units of factory namely, the "reformer" for the H_(2) and CO production, the "methanol reactor" for production of methonol adn a "separator" to separate CH_(3)OH form CO and H_(2) are schematically shown in figure. The flow of methonal from valve-3 is 10^(3)mol//sec. The factory is so designed that (2)/(3) of the CO is converted to CH_(3)OH. Assume that the feromer reaction goes to completion. CO+2H_(2)rarrCH_(3)OH Delta_(r) H=-100 R What is the flow of CO and H_(2) at valve-2 ?

Answer» <html><body><p>`CO:500 mol//sec,` `H_(2):<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a> mol//sec`<br/>`CO:<a href="https://interviewquestions.tuteehub.com/tag/1500-275573" style="font-weight:bold;" target="_blank" title="Click to know more about 1500">1500</a> mol//sec,` `H_(2):<a href="https://interviewquestions.tuteehub.com/tag/2500-297693" style="font-weight:bold;" target="_blank" title="Click to know more about 2500">2500</a> mol//sec`<br/>`CO:500 mol//sec,` `H_(2):2000 mol//sec`<br/>`CO:500 mol//sec,` `H_(2):1500 mol//sec`</p>Answer :b</body></html>


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