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A fair die is rolled. Consider the events E={1,3,5}, F = {2,3} and G={2,3,4,5}.Find P(E/F) and P(F/E) |
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Answer» <P> Solution :Here, S = {1,2,3,4,5,6}`EnnF`=`QUAD`3 `P(EnnF)`=`(N(EnnF))/(n(S))`=1/6 Also,P(F)=2/6 THEREFORE P(E/F)=`(P(EnnF))/(P(F))`=1/6/2/6=1/2. We have P (E)=3/6, P(F/E)=`(P(EnnF))/(P(E))` 1/6/3/6=1/3 |
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