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A fair die is tossed repeatedly. `A`wins if if is 1 or 2 on two consecutive tosses and `B`wins if it is 3,4,5 or 6 on two consecutive tosses. The probabilitythat `A`wins if the die is tossed indefinitely is`1//3`b. `5//21`c. `1//4`d. `2//5`A. `1//3`B. `5//21`C. `1//4`D. `2//5` |
Answer» Correct Answer - B Let `P(S)=P(1 or 2)=1//3` `P(F)=P(3or4or5or6)=2//3` `P(A "wins")=P[(SS orSFSSorSFSFSSor..)or(FSSorFSFFSSor...)]` `=((1)/(9))/(1-(2)/(9))+((2)/(27))/(1-(2)/(9))` `= 1/9xx9/7+2/27xx9/7` `=1/7+2/21=(3+2)/(21)=5/21` P(A swining)`=5/21,` P(B winning)`=16/21` |
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