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A fair die is tossed twice. What are the odds in favour of getting 4, 5, or 6 on the first toss and 1, 2, 3, or 4 on the second toss? (A) 1 : 3 (B) 3 : 1 (C) 1 : 2 (D) 2 : 1 |
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Answer» Correct option is:(C) 1 : 2 A fair dice is tossed twice. ∴ n(S) = 36 A: Getting 4, 5, or 6 on the first toss and Getting 1, 2, 3, or 4 on the second toss. ∴ A = {(4, 1), (4, 2), (4, 3), (4, 4), (5, 1), (5, 2), (5, 3), (5, 4), (6, 1), (6, 2), (6, 3), (6, 4)} ∴ P(A) = \(\frac {n(A)}{n(S)} = \frac {12} {36} = \frac {1}{3}\) ∴ Required answer = P(A) : P(A’) = 1 : 2 |
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