1.

A farmer completes two and half rounds of a square field of each side 40m. What is his displacement?​

Answer»

tion:10m, thus perimeter P=40mTime taken to COVER the boundary of 40 m =40 sThus in 1 second, the farmer covers a distance of 1 MNOW distance covered by the farmer in 2 min 20 seconds = 1×140=140mNow the TOTAL number of rotation the farmer MAKES to cover a distance of 140 meters = perimetertotaldistance =3.5 At this point, the farmer is at a point say B from the origin OThus the displacement s= 10 2 +10 2 from Pythagoras theorem.s=10 2 =14.14m



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