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A father's age is 3 times the sum of ages of his two sons. Five years later he will be twice the sum of ages of his two sons. Find the present age of the father |
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Answer» let the age of father be x and the sum of age of sum of two son be yx=3yx+5=2(y+10)x+5=2y+20x=2y+153y=2y+15y=15yrx=3(15)=45yr |
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