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A father's age is 3 times the sum of ages of his two sons. Five years later he will be twice the sum of ages of his two sons. Find the present age of the father. |
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Answer» F=3(S1+S2)F+5=2(S1+5+S2+5)=2(S1+S2)+20so F=2(S1+S2)+203(S1+S2)=2(S1+S2)+20so S1+S2=20so F=3×20=60 Years |
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