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    				| 1. | A film of water is formed between two straight parallel wires each `10 cm` long and at a seperation of `0.5 cm`. Calculate the work required to increase `1mm` distance between the wires. Surface tension of water `=72xx10^(-3)N//m`.A. `1.44xx10^(-5)xx10^(-5)J`B. `1.72xx10^(-5)J`C. `1.44xx10^(-4)J`D. `1.72xx10^(-4)J` | 
| Answer» Correct Answer - A As we increase the separation between the wire by `1mm`, the increase in surface area of the film is `/_A=2xx0.1xx10^(-3)=2xx10^(-4)m^(2)` (as there are two surfaces of film) So, increase in suface energy `/_U=S/_A=1.44xx10^(-5)J` Work done`=/_J` | |