InterviewSolution
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InterviewSolution
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A fire cracker is fired and it rises to a height of 1000 m. Find the velocity by which it was released and the time taken by it to reach the highest point (take a = 10 m/s²). |
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Answer» 1) h=1000m v= 0 m/s (at HIGHEST point) g= 9.8 m/s( taken to be negative ACCORDING to SIGN convention) Using 3rd equat. of motion,v^2= u^2 + 2as0 = u^2- 2*9.8*1000-u^2= -19600u^2= 19600u=140 m/s(2) u=140 m/s (as calculated above) 1st equation of motion,v= u+at0=140+(-9.8)t-140= -9.8t140= 9.8tt= 1400/98t= 14.3 secondst= 14 seconds( approximately) |
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