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InterviewSolution
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A first order decomposition reaction takes 40 minutes for 30% decomposition. Calculate its `t_(1//2)` value. |
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Answer» Here t = 400 min., `t_(1//2)=?` Let a = 100 `therefore` x = 30% of 100 = 30 using the formula, `{:(t=(2.303)/(K)log.(a)/(a-x),|,rArr,40=(2.302)/(K)log.(100)/(100-30)),(40=(2.303)/(K)log.(100)/(70),rArr,40=(2.303)/(K)(log10-log7),),(40=(2.303)/(K)(1-0.8451),rArr,40=(2.303)/(K)xx0.1549,),(K=(2.303xx0.1549)/(40),rArr,K=(0.357)/(40)=0.0089" min",):}` `therefore t_(1//2)=(0.693)/(K)=(0.693)/(0.0089)=77.86` min. |
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