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InterviewSolution
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A first order reaction has a rate constant of `0.0051 "min"^(-1)`. If we begin with `0.10M` concentration of the reaction , what concentration of reactant will remain in solution after 3 hours ? |
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Answer» Here , `[R]_(o) = 0.10M` , [R] = ? t = 3 hours = `3 xx 60 = 180` min `k = 0.0051 "min"^(-1)`. Using the formula k = `(2.303)/(t) log ([R]_(o))/([R]) = 0.0051 = (2.303)/(180) log.(0.10)/([R])` `log.(0.10)/([R]) = (0.0051 xx 180)/(2.303)` `log.(0.10)/([R]) = (0.918)/(2.303) = 0.3986` `therefore " " (0.10)/([R])` = antilog `(0.3986)` `(0.10)/([R]) = 2.503 implies [R] = (0.10)/(2.503) = 0.039` M |
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