1.

A first order reaction is found to have a rate constant k = 7.39xx10^(-5)s^(-1). Find the half life of this reaction.

Answer»

SOLUTION :For first order REACTION
`k=(2.303)/(t)"log"(a)/(a-X)`
For `t=t_(1//2), "" x=(a)/(2)`
`t_(1//2)=(2.303)/(k)"log"(a)/(a-(a)/(2))`
`=(2.303)/(k)log 2 = (2.303xx0.3010)/(7.39xx10^(-5))`
`= 9.38xx10^(3)s`.


Discussion

No Comment Found

Related InterviewSolutions