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A first order reaction takes 20 minutes for 25% decomposition. Calculate the time when 75% of the reaction will be completed. (Given, `log2=0.3010,log3=0.4771,log4=0.6021`) |
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Answer» `t_(25%)=20` min `k=(2.303)/(t)log((a)/(a-x))" "[{:(ato"Initial conc."),(xto" reacted"),(a-xto" remaining"):}]` `k=(2.303)/(20)log((cancel(100))/(cancel(75)))["Div. by"25]` `k=(2.303)/(20)(log4-log3)` `implies(2.303)/(20)xx(0.6021-0.4771)` `impliesk=(2.303)/(20)xx0.125s^(-1)` `t_(75%)=(2.303)/(k)log((cancel(100))/(cancel(25)))` `=(2.303xx20)/(2.303xx0.125)xx0.6021=t_(75%)=96.34sec`. |
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