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A first order reaction takes 40 min for `30%` decomposition. Calculate `t_(1//2)`. (Given `log 7 =0.845)`A. `33.2 m i n `B. `77.7 m i n`C. `22.7 m i n`D. `40 m i n ` |
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Answer» Correct Answer - 2 `30%` decomposition means that `x=30%` of `a=0.30a` As reaction is of 1st order, `k-(2.303)/(t)log.(a)/(a-x)=(2.303)/(40 min )log.(a)/(a-0.30a)=(2.303)/(40)xxlog.(10)/(7)"min"^(-1)` For a 1st order reaction `t_(1//2)=(0.693)/(k)=(0.693)/(8.918xx10^(-3)"min"^(-1))=77.7min` |
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