1.

A first order reaction takes 40 minutes for 30% decomposition. Calculate t_(1//2).

Answer»

SOLUTION :Applying the relation :
`k=(2.303)/(t)"log"([A]_(0))/([A])`
SUBSTITUTING the values, we have
`k=(2.303)/(40)"log"(100)/(70)=(2.303)/(40)xx0.1549=0.0089"min"^(-1)`
`t_(1//2)=(0.693)/(k)=(0.693)/(0.0089)=77.86` MINUTES


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