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A flake of glass (refractive index 1.5) is placed over one of the opening of a double-slit apparatus. The interference pattern displaced itself through seven successive maxima toward the side where the flake is placed. If wavelength of the light is `lambda = 600 nm`, then the thickness of the flake isA. 2100 nmB. 4200 nmC. 8400 nmD. none of above |
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Answer» Correct Answer - c (Shift) `= 7` (Position of central maxima) `implies (mu - 1)t (D)/(d) = 7 ((lambda D)/(d))` `:.t = (7 lambda)/(mu - 1)` ` implies t = (7(600))/(0.5)` `implies t = 8400 nm` |
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