1.

A flask is filled with `13 g` of an ideal gas at `27^(@)C` and its temperature is raised to `52^(@)C`. The mass of the gas that has to be released to maintain the temperature of the gas in the flask at `52^(@)C`, the pressure remaining the same isA. `2.5 g`B. `2.0 g`C. `1.5 g`D. `1.0 g`

Answer» Correct Answer - D
d. `PV prop` Mass of gas `xx` Temperature
In this problem pressure and volume remain constant, so
`M_(1) T_(1) = M_(2) T_(2) =` constant
`:. (M_(2))/(M_(1)) = (T_(1))/(T_(2)) = ((27 + 273))/((52 + 273)) = (300)/(325) = (12)/(13)`
`implies M_(2) = M_(1) xx (12)/(13) = 13 xx (12)/(13) g = 12 g`
i.e., the mass of gas released from the flask `= 13 g - 12 g = 1g`.


Discussion

No Comment Found

Related InterviewSolutions