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A gas at pressure P is abiabatically compressed so that its density becomes twice that of initial value. Given that `gamma=C_(p)//C_(v)=(7//5)` , What will be the final pressure of the gas ?A. `2p`B. `(7)/(5)`C. 2.63 pD. p

Answer» Correct Answer - C
For adiabatic process,`p_(2)V_(2)^(gamma)=p_(1)V_(1)^(gamma)`
`therefore"final pressure " p_(2)=p_(1)((V_(1))/(V_(2)))^(gamma)=p_(1)(rho_(2)/(rho_(1)))^(gamma)`
`p=((2)/(1))^(7//5)=2.63p`


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