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A flow of `10^(7)` electrons per second in a conducting wire constitutes a current ofA. `1.6xx10^(-26)A`B. `1.6xx10^(-12)A`C. `1.6xx10^(12)A`D. `1.6xx10^(26)A` |
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Answer» Correct Answer - B `I=(q)/(t)=(n e)/(t)=(10^(7)xx1.6xx10^(-19))/(1)` `=1.6xx10^(-12)A` |
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