1.

A fluid container is containing a liquid of density `rho` is accelerating upward with acceleration a along the inclined plane of inclination `alpha` as shown in the figure. Then the angle of inclination `theta` of free surface isA. `tan^(-1)[(a)/(gcosalpha)]`B. `tan^(-1)[(a+gsinalpha)/(gcosalpha)]`C. `tan^(-1)[(a-gsinalpha)/(g(1+cosalpha))]`D. `tan^(-1)[(a-gsinalpha)/(g(1-cosalpha))]`

Answer» Correct Answer - B
Apply pseudo force on a particle of mass `m`. Net force along the surface is zero.
`macostheta=mgcos[90-(theta-alpha)]`
`(a)/(g)costheta=gsin(theta-alpha)`
`(a)/(g)=(sinthetacosalpha)/(costheta)-(costhetasinalpha)/(costheta)`
`tantheta=((a)/(g)+sinalpha)/(cosalpha)=(a+gsinalpha)/(gcosalpha)`


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