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A fly wheel of mass 4 kg has moment of inertia `16 kg m^(2)`, then radius of gyration about the central axis perpendicular to its plane isA. 1mB. 2mC. 4mD. 16m |
Answer» Correct Answer - B `I = MK^(2)` `K = sqrt((I)/(m)) = sqrt((16)/(4)) = sqrt(4) = 2`. |
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