1.

A fly wheel of mass 4 kg has moment of inertia `16 kg m^(2)`, then radius of gyration about the central axis perpendicular to its plane isA. 1mB. 2mC. 4mD. 16m

Answer» Correct Answer - B
`I = MK^(2)`
`K = sqrt((I)/(m)) = sqrt((16)/(4)) = sqrt(4) = 2`.


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