A flywheel rotates with a uniform angular acceleration. Its angular speed increases from `2pirad//s` to `10pirad//s` in `4 s`. Find the number of revolutions in this period.

A flywheel rotates with a uniform angular acceleration. Its angular sp

1.	A flywheel rotates with a uniform angular acceleration. Its angular speed increases from `2pirad//s` to `10pirad//s` in `4 s`. Find the number of revolutions in this period.
Answer» `omega_(0)=2pi rad//s, omega=10 pi rad//s` `omega=omega_(0)+alpha t` ` 10 pi = 2 pi+alphaxx4implies alpha=2pi rad//s^(2)` `theta = omega_(0) t + (1)/(2)alpha t^(2)` `= 2pixx4+(1)/(2)xx2pixx(4^(2))` `= 8pi+16pi=24 pi rad` Number of revolutions `N=(theta)/(2pi)=(24pi)/(2pi)=12`

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A flywheel rotates with a uniform angular acceleration. Its angular speed increases from `2pirad//s` to `10pirad//s` in `4 s`. Find the number of revolutions in this period.

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