A flywheel starts rotating from rest when a torque is applied on it, with a uniform angular acceleration of 5 "rad"//s^(2). What is the angular displacement of the flywheel in the 5th Second ?

A flywheel starts rotating from rest when a torque is applied on it, w

1.	A flywheel starts rotating from rest when a torque is applied on it, with a uniform angular acceleration of 5 "rad"//s^(2). What is the angular displacement of the flywheel in the 5th Second ?
Answer» Solution :`omega_(0) = 0, ALPHA = 5 "rad"//s^(2), N = 5 s` Angular displacement in the 5th SECOND `=theta_("5th")`= ? `theta_("5th") = omega_(0) + alpha/2 (2n-1) = 0 +5/2 (2 xx 5-1) = 22.5` rad.