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(a) Following are the transition metal ions of 3d series : Ti^(4+),V^(2+),Mn^(3+),Cr^(3+) (Atomic numbers : Ti = 22, V = 23, Mn = 25, Cr = 24) Answer the following : (i) Which ion is most stable in an aqueous solution and why ? (ii) Which ion is a strong oxidising agent and why ? (iii) Which ion is colourless and why ? (b) Complete the following equations : (i) 2MnO_(4)^(-)+16H^(+)+5S^(2-)to (ii) KMnO_(4)overset("Heat")to |
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Answer» Solution :(a) (i) `Cr^(3+)` ion is most stable in an aqueous solution because it has stable half-filled `(t_(2g))` configuration. (ii) `Mn^(3+)` is a strong oxidising AGENT because `Mn^(2+)` formed as a result of reduction has half-filled `(d^(5))` stable configuration. (iii) `TI^(4+)` is colourless. There is no possibility of d-d transition and HENCE no absorption of LIGHT. (b) (i) `2MnO_(4)^(-)+16H^(+)+5S^(2-)to2Mn^(2+)+8H_(2)O+5S` (ii) `2KMnO_(4)overset("Heat")toK_(2)MnO_(4)+MnO_(2)+O_(2)` |
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