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A food chain consists of the following members. If the last member receives 30 J of energy, make a diagrammatic representation to show the flow of energy. Snake, Vulture, Plants and Rat. |
Answer» Plants (30000 J) → Rat(3000 J) → Snake (300 J) → Vulture (30 J) According to 10% Law The 10% of the energy present in snakes is passed to the vultures. Therefore, energy present in snakes = 30 x \((\frac{100}{10})\) = 300 J Similarly, energy present in rats = 300 x \((\frac{100}{10})\) = 3000 J and the energy present in plants = 3000 x \((\frac{100}{10})\) = 30000 J |
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