A force acts on an object of mass 2 kg at rest, for 0.5 s. After the force stops acting, the object travels a distance of 5 m in 2 s. Hence the magnitude of the force will be …

A force acts on an object of mass 2 kg at rest, for 0.5 s. After the f

1.	A force acts on an object of mass 2 kg at rest, for 0.5 s. After the force stops acting, the object travels a distance of 5 m in 2 s. Hence the magnitude of the force will be …
Answer» 5N 10 N 7.5 N 12.5 N SOLUTION :Herevelocityremainsconstant `v= (d )/( t) = (5 )/(2 ) = 2.5ms^(-1)` Nowinitialvelocity`v_(0)= 0 ms^(-1)` andforceacts on it As perNewtonssecondlaw of motion FORCEF `=(DELTA p )/(Delta t) = m(v-v_(0))/( Delta t )` `= 2(2.5 - 0)/(0.5)` `F= 10 N`